--- Amanuel Gabir <amanuel2674@...> wrote:

> Note: forwarded message attached.
>
>
> Hi Solomon,
> Thanks for willing to help me out.
> Here is my data set and my graph is attached to this
> e-mail. I was looking for 19 points on my graph but
> using this code, I got only 7 points, because some
> of the values of my independent variable repeat,
but over all I have 19 obervations, I wanted to put
19 points on my graph insead of 7 values.
> Thanks for you help in advance
> Amanuel,
>
>
> x
>
<-c(0.1,0.1,0.2,0.2,0.2,0.2,0.3,0.3,0.3,0.3,.4,1,1,1,1.5,2,2,2,2)
>
> prob <- exp(-4.65+2.98*x)/(1+exp(-4.65+2.98*x))
>
> plot(x, prob, type="l", xlab ="Soil moisture ",ylab
> ="Estimated probability, ")
> points(x,1:length(x)*0+ 0.001, pch="*")
>
>
> --- Solomon Christopher <sol_chris82@...>
> wrote:
>
> > Dear Amanuel,
> >
> > Can you make your question even more clear. You
> > can also provide the data so that I can help you
> > out.
> >
> > best,
> > Solomon.
> >
> >
> >
> > ---------------------------------
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> > Click here to know how.
>
>
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