Hi jerkos,
You want to test:
Ho: p <= 0
H1: p >0
H1: p >0
clearly this is a one-sided test.
Here your test statistic will be
t= r*sqrt(n-2)/sqrt(1-r*r)
= 0.32*sqrt(12-2)/sqrt(1-0.32*0.32)
[since r=sample correlation=0.32
and n= sample size =
12 ]
= 1.06892
Now this t is follows student t distribution with 12-2 = 10 degrees of freedom.
Now the table value of t at 10 degrees of freedom and 5% level of significance is 2.228139.
Since the calculated value (=1.06892) is less than the table value (=2.228139) therefore we accept Ho.
So our conclusion is " there is no evidence from the sample that the population correlation coefficient is different from zero."
Hope this helps.
I want to say another thing to you that I have seen
your problem two days ago but I can reply due to involvement with other works. Don't be discouraged...plz. we all the member are always keen to help each other. So if you have further problem in future then please don't hesitate to post it.
with regards,
Madan
jerkos <jerkos@...> wrote:
jerkos <jerkos@...> wrote:
>> >
>> > The following hypothesis are given:
>> >
>> > Ho: p is less or equal to 0
>> > H1: p is greater than 0
>> >
>> > A random sample of 12 observations indicated a correlation of .32
>> > Can we conclude that the correlation in the population is greater
>> than 0?
>> > Use the .05 significance level.
>> >
>> > t = r * sqrt(n-2)/sqrt(1-r^2) which would be .32 8 sqrt (10)
>> > sqrt(1-.32^2)
>> >
>> What do I do after this?Please please someone help me.Thank you
I've received t statistics.
Now you have to find critical value for t (one side for 0,05 and v=12-2
degrees of freedom or equel two side for 0,10) [t_crit = 1,812]
If t is equel or greather than critical valu you can reject Ho, if not, Ho
could be true.
Szamot
--------------
Madan Gopal Kundu
Room no 18, Sukhatme Hostel
Indian Agricultural Statistics Research Institute
Library Avenue, Pusa
New Delhi 12
Room no 18, Sukhatme Hostel
Indian Agricultural Statistics Research Institute
Library Avenue, Pusa
New Delhi 12
India
mobile: 91-9868788406
e-mail: madan4331@...
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