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#3586 From: Madan Kundu <madan4331@...>
Date:: Wed Jul 1, 2009 3:17 pm
Subject:: Difficulty in calculating MLE through NLM
madan4331
Offline Offline
Send Email Send Email
 

Dear Members,

 

Attached is the SAS XPORT file that I have imported into R using following code

library(foreign)

mydata<-read.xport("C:\\ctf.xpt")

print(mydata)

 

I am trying to maximize logL in order to find Maximum Likelihood Estimate (MLE) of 5 parameters (alpha1, beta1, alpha2, beta2, p) using NLM function in R as follows.

 

# Defining Log likelihood – In the function it is noted as logL

> library(stats)

> loglike1<- function(x)

+ {

+ alpha1<-x[1]

+ beta1<-x[2]

+ alpha2<-x[3]

+ beta2<-x[4]

+ p<-x[5]

+ n<- mydata[3]

+ e<-mydata[4]

+ f1<- ((1+beta1/e)^(-n))*((1+e/beta1)^(-alpha1))*gamma(alpha1+n)/(gamma(n+1)*gamma(alpha1))

+ f2<- ((1+beta2/e)^(-n))*((1+e/beta2)^(-alpha2))*gamma(alpha2+n)/(gamma(n+1)*gamma(alpha2))

+ logL=sum(log(p*f1+(1-p)*f2))

+ logL<- -logL

+ }

 

# Supplying starting parameter values

> theta<-c(.2041,.0582, 1.4150, 1.8380,0.0969)

 

# Calculating MLE using NLM function

> result<- nlm(loglike1, theta, hessian=TRUE, print.level=1)

 

Now the problem is, this is not working as there is no improvement in final parameter estimate over starting values and NLM just stops just after 1 iteration with gradient value of all the 5 parameters as zero. I have tried other set of starting values, but then also I am getting final parameter estimates similar to starting values and iteration stops just after one step. When I check for warnings, R displays following kind of warnings:

  • NA/Inf replaced by maximum positive value
  • value out of range in 'gammafn'

 

Please suggest what I should do. I am expecting the final MLE of alpha1, alpha2, beta1 and beta2 greater than 0 and P should lie between 0 to 1.

 
Thanks & Regards,
--------------

Madan Gopal Kundu
Biostatistician, Ranbaxy Labs. Ltd.
Gurgaon, Haryana
India
mobile: 91-9868788406
 


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1 of 1 File(s)


#3585 From: lara hara <lara124000@...>
Date:: Tue Jun 30, 2009 5:18 pm
Subject:: Re: SEM -Amos, model fit modifications help-reg
lara124000
Offline Offline
Send Email Send Email
 
Thanks . I will try and inform

lara

--- On Mon, 29/6/09, vikas ait <vikasait@...> wrote:

From: vikas ait <vikasait@...>
Subject: Re: [Statisticians_group] SEM -Amos, model fit modifications help-reg
To: Statisticians_group@...
Date: Monday, 29 June, 2009, 11:03 AM

Lara,

I haven’t worked on AMOS. I am trying to understand the problem.

You said the data doesn’t fit the model.Did you try probability plot to understand whether data depicts normal / uniform distribution. If that is worked out , Did you try finding out assignable causes and random causes and caliberate the model, if yes did you now conclude that the data doesn’t fit the model, so in this case :

We now need to focus on experimental values (by controlling other factors that influence the model)

Guess, multiple regression analysis is a good technique for it.

Let me know the exact point where you are stuck up
 
Regards,
Vikas

--- On Sun, 28/6/09, lara124000 <lara124000@yahoo. com> wrote:

From: lara124000 <lara124000@yahoo. com>
Subject: [Statisticians_ group] SEM -Amos, model fit modifications help-reg
To: Statisticians_ group@yahoogroup s.co.in
Date: Sunday, 28 June, 2009, 12:15 PM


Dear all

I am using AMOS for my data analysis. My data is not fit with my model and model need modifications. Will anybody highlight willingness and help on this area so that I can complete my analysis

lara



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#3584 From: Rakesh Saroj <coolvershabhu@...>
Date:: Tue Jun 30, 2009 3:55 am
Subject:: JOB
coolvershabhu
Offline Offline
Send Email Send Email
 
Hello Friends,
This is regarding openings with one of the Clinical research organisation in hyderabad.
for the post of BIOSTATISTICIAN.
With experiance in handling clinical trials in SAS and other statistical softwares.
Education Qualifications: M.Sc/PhD (Biostatistics) 
Experience: atleast 3 to 5 years in clinical trials.
If any one interested for this position forward your updated resume to ravichand@... with the following details:
current ctc:
expected ctc:
notice period:
With Best Regards,
Sridhar


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#3583 From: "swannies1983" <split_city@...>
Date:: Mon Jun 29, 2009 8:08 am
Subject:: Re: Help with mixed models question
swannies1983
Offline Offline
Send Email Send Email
 


--- In Statisticians_group@..., "swannies1983" <split_city@...> wrote:
>
> Hi there,
>
> I ran a study in which I investigated changes in several variables leading into upper airway obstruction in sleep apnoea patients. Sleep apnoea is a condition in which the airway closes (apnoeas) repetitively throughout the night.
>
> I studied six sleep apnoea patients. Each patient had a variable number of apnoeas for analysis. One of the variables I
> looked at was gastric pressure (Pga) at end expiration. Here is a link
> showing the mean Pga for the last four breaths leading into upper airway collapse for the six patients http://users.adam.com.au/swans1983/Gastric%20Pressure.jpg The left most point is average awake data. Fot this data, I averaged about 30-40 breaths of Pga data from wakefulness in each subject. Please also see the left most data of the "Pga Pressure Data" excel file located here http://users.adam.com.au/swans1983/ The factors and levels are as follows:
>
> 1) Subject (six patients)
> 3) Apnoea# (Variable between subjects)
> 4) Breath# (Four breaths. Not all apnoeas have four breaths)
> 5) Gastric pressure (% of wake) *I have shown absolute values in the graph but for the purpose of my analysis, I have defined all breaths as a % of wake.
>
> I wish to determine whether each of the four breaths prior to apnoeas is different from wake. I have been trying to use linear mixed models in SPSS for this. Is there a syntax I can use to determine if each of the four breaths is different from 100(%)?
>
> I also thought of another method which could be used to determine if those four breaths are different from wake. Firstly, I decided to use only 30 wake breaths for each subject. So now I have:
>
> 1) Stage (0=wake, 1=apnoea)
> 2) Subject (six patients)
> 3) Period# (only 1 for wake stage, but many for apnoea stage. Variable
> numbers for each subject for apnoea stage)
> 4) Breath# (30 breaths for wake data and 4 breaths for apnoea stage. Not all apnoeas had four breaths)
> 5) Gastric pressure (absolute values)
>
> This is the syntax I tried using:
>
> MIXED Pga BY Stage Period Breath#
> /CRITERIA=CIN(95) MXITER(100) MXSTEP(5) SCORING(1)
> SINGULAR(0.000000000001) HCONVERGE(0, ABSOLUTE) LCONVERGE(0, ABSOLUTE)
> PCONVERGE(0.000001, ABSOLUTE)
> /FIXED=Stage Breath# Stage*Breath# | SSTYPE(3)
> /METHOD=REML
> /RANDOM=INTERCEPT | SUBJECT(Subject) COVTYPE(VC)
> /REPEATED=Stage*Period*Breath# | SUBJECT(Subject) COVTYPE(AR1)
> /EMMEANS=TABLES(Stage) COMPARE ADJ(SIDAK)
> /EMMEANS=TABLES(Breath#) COMPARE ADJ(SIDAK)
> /EMMEANS=TABLES(Stage*Breath#)
> /TEST = "average of wake vs breath 1 of apnoea" Stage*Breath# 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 -1 0 0 0.
>
> I thought this test would compare breath#1 of stage 1 with the average value of the 30 breaths of stage 0. I would then change the last bit of the code for the other 3 breaths. However, when I run the model, I get the error message
>
> "Custom hypothesis test 1 (average of wake vs breath 1 of apnoea) will not be performed because the L matrix is not estimable."
>
> Any ideas what I am doing wrong?

I was able to fix the the above problem via different coding but I am still interested in how to determine if breath data is different from 100% as described in my first part of my post.


#3582 From: vikas ait <vikasait@...>
Date:: Mon Jun 29, 2009 5:33 am
Subject:: Re: SEM -Amos, model fit modifications help-reg
vikasait
Offline Offline
Send Email Send Email
 
Lara,

I haven’t worked on AMOS. I am trying to understand the problem.

You said the data doesn’t fit the model.Did you try probability plot to understand whether data depicts normal / uniform distribution.If that is worked out , Did you try finding out assignable causes and random causes and caliberate the model, if yes did you now conclude that the data doesn’t fit the model, so in this case :

We now need to focus on experimental values (by controlling other factors that influence the model)

Guess, multiple regression analysis is a good technique for it.

Let me know the exact point where you are stuck up
 
Regards,
Vikas

--- On Sun, 28/6/09, lara124000 <lara124000@...> wrote:

From: lara124000 <lara124000@...>
Subject: [Statisticians_group] SEM -Amos, model fit modifications help-reg
To: Statisticians_group@...
Date: Sunday, 28 June, 2009, 12:15 PM


Dear all

I am using AMOS for my data analysis. My data is not fit with my model and model need modifications. Will anybody highlight willingness and help on this area so that I can complete my analysis

lara



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#3581 From: "lara124000" <lara124000@...>
Date:: Sun Jun 28, 2009 6:45 am
Subject:: SEM -Amos, model fit modifications help-reg
lara124000
Offline Offline
Send Email Send Email
 
Dear all

I am using AMOS for my data analysis. My data is not fit with my model and model
need modifications.Will anybody highlight willingness and help on this area so
that I can complete my analysis

lara

#3580 From: "swannies1983" <split_city@...>
Date:: Sat Jun 27, 2009 4:04 pm
Subject:: Help with mixed models question
swannies1983
Offline Offline
Send Email Send Email
 
Hi there,

I ran a study in which I investigated changes in several variables leading into
upper airway obstruction in sleep apnoea patients. Sleep apnoea is a condition
in which the airway closes (apnoeas) repetitively throughout the night.

I studied six sleep apnoea patients. Each patient had a variable number of
apnoeas for analysis. One of the variables I
looked at was gastric pressure (Pga) at end expiration. Here is a link
showing the mean Pga for the last four breaths leading into upper airway
collapse for the six patients
http://users.adam.com.au/swans1983/Gastric%20Pressure.jpg The left most point is
average awake data. Fot this data, I averaged about 30-40 breaths of Pga data
from wakefulness in each subject. Please also see the left most data of the "Pga
Pressure Data" excel file located here http://users.adam.com.au/swans1983/ The
factors and levels are as follows:

1) Subject (six patients)
3) Apnoea# (Variable between subjects)
4) Breath# (Four breaths. Not all apnoeas have four breaths)
5) Gastric pressure (% of wake) *I have shown absolute values in the graph but
for the purpose of my analysis, I have defined all breaths as a % of wake.

I wish to determine whether each of the four breaths prior to apnoeas is
different from wake. I have been trying to use linear mixed models in SPSS for
this. Is there a syntax I can use to determine if each of the four breaths is
different from 100(%)?

I also thought of another method which could be used to determine if those four
breaths are different from wake. Firstly, I decided to use only 30 wake breaths
for each subject. So now I have:

1) Stage (0=wake, 1=apnoea)
2) Subject (six patients)
3) Period# (only 1 for wake stage, but many for apnoea stage. Variable
numbers for each subject for apnoea stage)
4) Breath# (30 breaths for wake data and 4 breaths for apnoea stage. Not all
apnoeas had four breaths)
5) Gastric pressure (absolute values)

This is the syntax I tried using:

MIXED Pga BY Stage Period Breath#
   /CRITERIA=CIN(95) MXITER(100) MXSTEP(5) SCORING(1)
SINGULAR(0.000000000001) HCONVERGE(0, ABSOLUTE) LCONVERGE(0, ABSOLUTE)
PCONVERGE(0.000001, ABSOLUTE)
   /FIXED=Stage Breath# Stage*Breath# | SSTYPE(3)
   /METHOD=REML
   /RANDOM=INTERCEPT | SUBJECT(Subject) COVTYPE(VC)
   /REPEATED=Stage*Period*Breath# | SUBJECT(Subject) COVTYPE(AR1)
   /EMMEANS=TABLES(Stage) COMPARE ADJ(SIDAK)
   /EMMEANS=TABLES(Breath#) COMPARE ADJ(SIDAK)
   /EMMEANS=TABLES(Stage*Breath#)
/TEST = "average of wake vs breath 1 of apnoea" Stage*Breath# 1/30 1/30 1/30
1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30
1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 1/30 -1 0 0 0.

I thought this test would compare breath#1 of stage 1 with the average value of
the 30 breaths of stage 0. I would then change the last bit of the code for the
other 3 breaths. However, when I run the model, I get the error message

"Custom hypothesis test 1 (average of wake vs breath 1 of apnoea) will not be
performed because the L matrix is not estimable."

Any ideas what I am doing wrong?

Thanks

Daniel

#3579 From: Rakesh Saroj <coolvershabhu@...>
Date:: Fri Jun 26, 2009 8:41 am
Subject:: job
coolvershabhu
Offline Offline
Send Email Send Email
 
#3578 From: Andrew Hartley <khahstats@...>
Date:: Thu Jun 25, 2009 9:55 pm
Subject:: Re: accept
khahstats
Offline Offline
Send Email Send Email
 
Faisal,
Please specify the degree to which you like statistics, on a scale of 1 to 10 (smile).

--- On Thu, 6/25/09, Faisal Jamil <faisaljamil53@...> wrote:

From: Faisal Jamil <faisaljamil53@...>
Subject: [Statisticians_group] accept
To: Statisticians_group@...
Date: Thursday, June 25, 2009, 12:39 PM

i accept and i like category of statistic and hope you accept my request



#3577 From: Faisal Jamil <faisaljamil53@...>
Date:: Thu Jun 25, 2009 4:39 pm
Subject:: accept
faisaljamil53
Offline Offline
Send Email Send Email
 
i accept and i like category of statistic and hope you accept my request


#3576 From: "time pass" <satyaki1983@...>
Date:: Wed Jun 24, 2009 4:38 am
Subject:: Calling R in matlab
satyaki1983
Offline Offline
Send Email Send Email
 
Hi everyone,

I want to call a function of R (cov.mcd which is in the package MASS of R) in a
matlab function. What I mean is the following.

Suppose I am writing a program in matlab and I want to use this particular R
function cov.mcd(dataset) within the matlab program.

If anyone can help me in this issue I will be grateful.

Thanks and Regards,

Satyaki

#3575 From: KAUSHIK BHATTACHARJEE <kabonline07@...>
Date:: Tue Jun 23, 2009 5:47 am
Subject:: Re: Co-varaince, R , R square
kabonline07
Offline Offline
Send Email Send Email
 

 Hi ,
What is true for co-variance is true for correlation ...except correlation is a unit free measure & alwys between +1 & -1.See the formula of both of them....u will find it on your own....
If the relationship is quadratic ...both correlation & covariance will give it a measure 'zero'....as if no relation exist between them... that is why  I wrote linear......
hope this helps...
 
Kaushik Bhattacharjee
 


From: vikas ait <vikasait@...>
To: Statisticians_group@...
Sent: Monday, June 22, 2009 5:31:21 PM
Subject: Re: [Statisticians_group] Co-varaince, R , R square

Hi,
I think the relationship that you mentioned is
correlation and not covariance
 Y = f ( X)
where f is relationship between variables and it can be linear , quadratic opr cubic.
I am interested looking at what is covariance , R and R square and tneir significance.
 
Regards,
Vikas

--- On Mon, 22/6/09, KAUSHIK BHATTACHARJEE <kabonline07@ yahoo.com> wrote:

From: KAUSHIK BHATTACHARJEE <kabonline07@ yahoo.com>
Subject: Re: [Statisticians_ group] Co-varaince, R , R square
To: Statisticians_ group@yahoogroup s.co.in
Date: Monday, 22 June, 2009, 2:00 PM

co-variance is the measure which ties to figure out the relationship( linear) b/w two variables... .X&Y
if with increasing X , Y on the avg increases ..it is +ve.. If Y decreases on the avg it is -ve. If Y remains stable at a more or less constatnt level....it is zero. Formula is E[(X-E(X))(Y- E(Y))]
It is not free from unit & can take any value.
Pls consult any standard text book  for details....
 
Kaushik Bhattacharjee
 


From: vikas ait <vikasait@yahoo. co.in>
To: Statisticians_ group@yahoogroup s.co.in
Sent: Monday, June 22, 2009 12:17:21 PM
Subject: [Statisticians_ group] Co-varaince, R , R square

Hi All,
I have been trying to figure out the difference between
variance and co-variance.
Can anyone help me out with this?
To my understanding variance is the spread across the mean and I am not
very sure then what is co-variance.
While going through Minitab tool, I came across R and R square in scatter plot.
Though I have gine through help in minitab but I was keen at
understanding conceptually R and R square and their significance.
How do they explain the scatter plot?
Seeking guidance on above.
Regards,
Vikas


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#3574 From: "informatics2005" <informatics2005@...>
Date:: Tue Jun 23, 2009 5:10 am
Subject:: mixed paired&unpaired analysis
informatics2005
Offline Offline
Send Email Send Email
 
hi
pls anyone knows about mixed paired &unpaired analysis?

#3573 From: "Tracy Wolfe" <twolfe@...>
Date:: Mon Jun 22, 2009 9:52 pm
Subject:: Opportunity Statistician/Programmer
twolfe20032003
Offline Offline
Send Email Send Email
 
Hello,

My name is Tracy Wolfe, Vice-President of Zingaro & Company, an executive search
consulting firm specializing in the search and selection of executives for the
healthcare industry.

I am currently working on an exciting assignment with my client, an
international contract research organization with offices in India and Chicago,
IL.  We are looking for dynamic individuals interested in joining the
Statistics/SAS Programming team.  We seek candidates with a Master's degree, PhD
preferred, and a minimum of 5 years of experience in statistics, biostatistics
or a closely related field.  Additionally, we are looking for candidates with
SAS programming experience.  Individuals who are creative and thrive in an
evolving environment should consider this opportunity.

I would be grateful for your assistance in our efforts.  Please let me know of
any outstanding candidates who may be interested in this opportunity or have
them contact me directly.

Respectfully,

Tracy Wolfe
Vice President
____________________________________________
Zingaro & Company
21936 Briarcliff Drive - Briarcliff, TX 78669-2012
Phone (512) 327-7275 - Fax (512) 327-1774
www.zingaro.com
____________________________________________


Job Profile
Senior Statistician

The Company:
CliniRx Research is a part of JK Organization.  JK is a 125 year old, $2.5
billion enterprise with presence in over 40 countries and leadership in multiple
sectors.

Over the past several years, CliniRx Research has become one of the fastest
growing CROs in the country. The group's passion for excellence and its
commitment to the cause of human advancement, create an atmosphere for
achievement in the global research business.

Scope of the Job:
This new position, located at US company headquarters in Chicago, IL reports to
the Manager of Statistics.  You will serve as the lead statistician for the
analysis of clinical trials being conducted by the company.  You will interact
with the data management department, the clinical development department, and
medical writing.  Additionally, you will interact with the client to carry out
the clinical trial.  This job requires knowledge of statistics in clinical
trials, SAS programming, good communication skills, and excellent attention to
detail.

Responsibilities:
1. You will serve as the lead statistician on project teams for the execution of
clinical trials.  This includes:
­ Regular contact with the client.
­ Coordinating the planning and execution of the statistics related tasks as per
the contract.
­ You will work with the project team to establish a clear project scope and
timeline.
­ Working with the study data manager to ensure project deliverables are
achieved and in compliance with regulatory requirements.
­ You will ensure high quality, on time statistical deliverables.
­ Managing the financial aspects for the statistical portion of the project.
­ Working closely with the programmers to coordinate deliverables.

2. Preparation and review of statistical analysis plans in accordance with the
study protocol for more complicated or unconventional clinical trials.
3. Writes and reviews statistical method section for protocols independently.
4. Estimates sample sizes for clinical trials.
5. Advises clients on statistical design issues.
6. Performs QC of tables, listings, graphs, and derived datasets, particularly
those of a more complicated nature or those used for efficacy analyses.
7. Reviews CRFs and data management plans.
8. Can independently develop computer programs to generate tables, listings, and
graphs using SAS as outlined by the statistical analysis plan.   Candidates must
have an in-depth understanding of p-values.
9. Performs quality review of statistics deliverables to clients.
10. Works with programmers to ensure statistical analyses are accurate and
carried out correctly.
11. Reviews clinical study reports.
12. May assist in business development activities including study pricing and
new business acquisition.
13. Adheres to all study/project timelines.
14. Documents work so other statisticians and programmers can check or modify
work.
15. Suggests process improvements for work procedures.
16. Assists with the training and mentoring of new employees as needed.
17. Adheres to all policies, procedures, SOPs, and training plans.
18. Leads and/or contributes to internal process improvement initiatives.
19. Files study documents into Biometrics internal files.
20. Reviews draft protocols and CRFs for potential data collection and
representation, or database structure problems.  Provides feedback to the
project team.
21. Other duties as assigned.


Candidate Requirements:
We seek a statistician with a minimum of 5 years of experience within the
pharmaceutical industry and experience programming with SAS for statistical
analysis.

We seek a professional with a Master's Degree or PhD in statistics,
biostatistics, or a closely related field.

Candidates should have a sound understanding of Good Statistical Practices and
various regulatory requirements (FDA, EU, ICH), knowledge of clinical trial
design, FDA regulations, and quality standards.


Compensation:
A compensation package will be designed to attract outstanding talent and will
include a base salary plus benefits.

#3572 From: vikas ait <vikasait@...>
Date:: Mon Jun 22, 2009 12:01 pm
Subject:: Re: Co-varaince, R , R square
vikasait
Offline Offline
Send Email Send Email
 
Hi,
I think the relationship that you mentioned is
correlation and not covariance
 Y = f ( X)
where f is relationship between variables and it can be linear , quadratic opr cubic.
I am interested looking at what is covariance , R and R square and tneir significance.
 
Regards,
Vikas

--- On Mon, 22/6/09, KAUSHIK BHATTACHARJEE <kabonline07@...> wrote:

From: KAUSHIK BHATTACHARJEE <kabonline07@...>
Subject: Re: [Statisticians_group] Co-varaince, R , R square
To: Statisticians_group@...
Date: Monday, 22 June, 2009, 2:00 PM

co-variance is the measure which ties to figure out the relationship( linear) b/w two variables... .X&Y
if with increasing X , Y on the avg increases ..it is +ve. If Y decreases on the avg it is -ve. If Y remains stable at a more or less constatnt level....it is zero. Formula is E[(X-E(X))(Y- E(Y))]
It is not free from unit & can take any value.
Pls consult any standard text book  for details....
 
Kaushik Bhattacharjee
 


From: vikas ait <vikasait@yahoo. co.in>
To: Statisticians_ group@yahoogroup s.co.in
Sent: Monday, June 22, 2009 12:17:21 PM
Subject: [Statisticians_ group] Co-varaince, R , R square

Hi All,
I have been trying to figure out the difference between
variance and co-variance.
Can anyone help me out with this?
To my understanding variance is the spread across the mean and I am not
very sure then what is co-variance.
While going through Minitab tool, I came across R and R square in scatter plot.
Though I have gine through help in minitab but I was keen at
understanding conceptually R and R square and their significance.
How do they explain the scatter plot?
Seeking guidance on above.
Regards,
Vikas


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#3571 From: tenveer <ten.veer@...>
Date:: Mon Jun 22, 2009 9:58 am
Subject:: Re: Co-varaince, R , R square
ten.veer
Offline Offline
Send Email Send Email
 
http://www.cs.otago.ac.nz/cosc453/student_tutorials/principal_components.pdf


Study the 2.1 section for understanding.......

On Mon, Jun 22, 2009 at 12:47 PM, vikas ait <vikasait@...> wrote:


Hi All,
I have been trying to figure out the difference between
variance and co-variance.
Can anyone help me out with this?
To my understanding variance is the spread across the mean and I am not
very sure then what is co-variance.
While going through Minitab tool, I came across R and R square in scatter plot.
Though I have gine through help in minitab but I was keen at
understanding conceptually R and R square and their significance.
How do they explain the scatter plot?
Seeking guidance on above.
Regards,
Vikas


Cricket on your mind? Visit the ultimate cricket website. Enter now!



#3570 From: KAUSHIK BHATTACHARJEE <kabonline07@...>
Date:: Mon Jun 22, 2009 8:30 am
Subject:: Re: Co-varaince, R , R square
kabonline07
Offline Offline
Send Email Send Email
 
co-variance is the measure which ties to figure out the relationship(linear) b/w two variables....X&Y
if with increasing X , Y on the avg increases ..it is +ve. If Y decreases on the avg it is -ve. If Y remains stable at a more or less constatnt level....it is zero. Formula is E[(X-E(X))(Y-E(Y))]
It is not free from unit & can take any value.
Pls consult any standard text book  for details....
 
Kaushik Bhattacharjee
 


From: vikas ait <vikasait@...>
To: Statisticians_group@...
Sent: Monday, June 22, 2009 12:17:21 PM
Subject: [Statisticians_group] Co-varaince, R , R square

Hi All,
I have been trying to figure out the difference between
variance and co-variance.
Can anyone help me out with this?
To my understanding variance is the spread across the mean and I am not
very sure then what is co-variance.
While going through Minitab tool, I came across R and R square in scatter plot.
Though I have gine through help in minitab but I was keen at
understanding conceptually R and R square and their significance.
How do they explain the scatter plot?
Seeking guidance on above.
Regards,
Vikas


Cricket on your mind? Visit the ultimate cricket website. Enter now!



#3569 From: Patrick Burns <patrick@...>
Date:: Mon Jun 22, 2009 7:43 am
Subject:: Re: Singularity of a matrix and Ridge parameter
burnsstat
Offline Offline
Send Email Send Email
 
Not a direct answer to your question,
but in finance it is common to use a
factor model to create a variance matrix
when there are more variables than
observations.

R code to do that (including the possibility
of missing values) is available on the
Public Domain page of www.burns-stat.com.


Patrick Burns
patrick@...
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of "The R Inferno" and "A Guide for the Unwilling S User")


time pass wrote:
>
>
>
> Hi all,
>
> I am dealing with a problem where I got a sample covariance matrix
> singular since it is of high dimension. Now I came across some paper
> where I got some suggestions to use ridge parameter but there I could
> not find any algorithm for finding the best ridge parameter. I am
> wondering if any one have ever faced this kind of problem could you
> please help me? Also if you have done such work do you any code for it?
> I will really appreciate your help. Thanks in advance.
>
> Thanks and Regards,
>
> Satyaki
>
>

#3568 From: vikas ait <vikasait@...>
Date:: Mon Jun 22, 2009 6:47 am
Subject:: Co-varaince, R , R square
vikasait
Offline Offline
Send Email Send Email
 
Hi All,
I have been trying to figure out the difference between
variance and co-variance.
Can anyone help me out with this?
To my understanding variance is the spread across the mean and I am not
very sure then what is co-variance.
While going through Minitab tool, I came across R and R square in scatter plot.
Though I have gine through help in minitab but I was keen at
understanding conceptually R and R square and their significance.
How do they explain the scatter plot?
Seeking guidance on above.
Regards,
Vikas


Cricket on your mind? Visit the ultimate cricket website. Enter now!

#3567 From: "time pass" <satyaki1983@...>
Date:: Mon Jun 22, 2009 3:38 am
Subject:: Singularity of a matrix and Ridge parameter
satyaki1983
Offline Offline
Send Email Send Email
 
Hi all,

I am dealing with a problem where I got a sample covariance matrix singular
since it is of high dimension. Now I came across some paper where I got some
suggestions to use ridge parameter but there I could not find any algorithm for
finding the best ridge parameter. I am wondering if any one have ever faced this
kind of problem could you please help me? Also if you have done such work do you
any code for it? I will really appreciate your help. Thanks in advance.

Thanks and Regards,

Satyaki

#3566 From: "shahaakriti" <shahaakriti@...>
Date:: Thu Jun 18, 2009 7:16 pm
Subject:: Urgent Opening for the position of Analyst-Marketing Analytics,Dellhi
shahaakriti
Offline Offline
Send Email Send Email
 
Hi

There is an opening for the position of Analytics Manager with a leading
Consulting Company.

Position: Analytics Manager
Location: Bangalore/Gurgaon

Job Profile:

Help the clients create valuable insights from data that lower marketing costs
and improve marketing effectiveness and efficiency.

Help the clients design/ implement marketing programs and campaigns that
stimulate incremental sales, generate repeat purchases, reduce costs, strengthen
customer relations, and extend customer life span.

Help develop and interpret statistical models for targeted acquisition,
retention, cross-sell, customer lifetime value or behavioral segmentation models
using predictive modeling techniques that include linear and logistic
regression, cluster analysis, neural nets and other statistical techniques.


Skills Required:

Experienced professional with a minimum of 6 - 12 years of relevant experience
in client management, Data Analytics, Reporting, Modeling and Regression

Education
B.Tech/MBA/Master degree in Statistics/Econometrics/ Economics

If interested, please send your updated CV in word format along with following
details -

Total Exp (Post Qualification)
Current CTC
Expected CTC
Notice Period
Current Location

Regards
Aakriti Shah
HR Consultant
Empyrean Partners
aakriti.shah@...

#3565 From: Rakesh Saroj <coolvershabhu@...>
Date:: Wed Jun 17, 2009 3:01 am
Subject:: Vacancy,IIHMR,ICMR
coolvershabhu
Offline Offline
Send Email Send Email
 
  job in IIHMR Jaipur check this link or go IIHMR home page 
 
in ICMR
 
 


Cricket on your mind? Visit the ultimate cricket website. Enter now!

#3564 From: vikas ait <vikasait@...>
Date:: Tue Jun 16, 2009 12:48 pm
Subject:: Re: Cauchy,Chi square distribution
vikasait
Offline Offline
Send Email Send Email
 
Thanks Amani,
 
So median is central tendency of measure for Cauchy distribution.
But I am not convinced with statement that "Cauchy distribution is suitable for data that contain outliers or that extreme values appear with high probabilities"
Correct me if I am wrong, I think the purpose of distribution is to understand the data.
Data itself may or may not contain outliers.
Also if I just need to isolate/highlight/understand/focus on outliers
then Box and whisker plot is equally good.
But my question is currently at the distribution level.Once i decide the distribution of data then box and whisker plot will help me interpret the distribution of data.
Will really appreciate, if you list example where chi square or even cauchy distribution will be preferred over normal distribution.
 
Regards,
Vikas
 


--- On Tue, 16/6/09, amani abubaker <amanifeps2010@...> wrote:

From: amani abubaker <amanifeps2010@...>
Subject: Re: [Statisticians_group] Cauchy,Chi square distribution
To: Statisticians_group@...
Date: Tuesday, 16 June, 2009, 3:59 PM

Both normal  and Cauchy distributions are symmetric ones.this is unlike Chi-square  distribution as it is asymmetric distributions.
Cauchy distribution is suitable for data that contain outliers or that extreme values appear with high probabilities. Cauchy distribution doesnot have a mean so if you work with it you can speak about its median. 

--- On Tue, 16/6/09, vikas ait <vikasait@yahoo. co.in> wrote:

From: vikas ait <vikasait@yahoo. co.in>
Subject: Re: [Statisticians_ group] Cauchy,Chi square distribution
To: Statisticians_ group@yahoogroup s.co.in
Date: Tuesday, 16 June, 2009, 9:53 AM

Kaushik ,
Thanks for the input.
This makes me a little familiar with Cauchy distribution.
Will appreciate, if you can give me some more clarity on
what and how part of chi square.
and how does chi square, Cauchy, normal distributions differ conceptually.
Regards,
Vikas


--- On Tue, 16/6/09, KAUSHIK BHATTACHARJEE <kabonline07@ yahoo.com> wrote:

From: KAUSHIK BHATTACHARJEE <kabonline07@ yahoo.com>
Subject: Re: [Statisticians_ group] Cauchy,Chi square distribution
To: Statisticians_ group@yahoogroup s.co.in
Date: Tuesday, 16 June, 2009, 10:20 AM

Cauchy is t-distribution with 1 df---. t-distribution  is  suitable for modelling rvs which are supposed to have  fat tailed(compared to normal) distributions (e.g. Financial returns in higher frequency like daily or intra-day).
I have modelling experience in regression where the errror terms taht have sufficent reasopn to believe non-normal ----I have tried to model them using t-distrbution. .....
 
Kaushik Bhattacharjee
 


From: vikas ait <vikasait@yahoo. co.in>
To: Statisticians_ group@yahoogroup s.co.in
Sent: Monday, June 15, 2009 6:41:37 PM
Subject: [Statisticians_ group] Cauchy,Chi square distribution


Dear All,
 
I work in software industry and most of data I synthesisie is continuous in nature.
I generally use histogram to understand vraiations using basis of normal disribution .(mean=median= mode)
I am curious to learn what and how part of  chi square and cauchy distibution.
Has anyone used the above distributions? , if yes can you throw more light on it.
Seeking guidance on it.
 
 
Regards,
Vikas


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#3563 From: amani abubaker <amanifeps2010@...>
Date:: Tue Jun 16, 2009 10:29 am
Subject:: Re: Cauchy,Chi square distribution
amanifeps2010
Offline Offline
Send Email Send Email
 
Both normal  and Cauchy distributions are symmetric ones.this is unlike Chi-square  distribution as it is asymmetric distributions.
Cauchy distribution is suitable for data that contain outliers or that extreme values appear with high probabilities.Cauchy distribution doesnot have a mean so if you work with it you can speak about its median. 

--- On Tue, 16/6/09, vikas ait <vikasait@...> wrote:

From: vikas ait <vikasait@...>
Subject: Re: [Statisticians_group] Cauchy,Chi square distribution
To: Statisticians_group@...
Date: Tuesday, 16 June, 2009, 9:53 AM

Kaushik ,
Thanks for the input.
This makes me a little familiar with Cauchy distribution.
Will appreciate, if you can give me some more clarity on
what and how part of chi square.
and how does chi square, Cauchy, normal distributions differ conceptually.
Regards,
Vikas


--- On Tue, 16/6/09, KAUSHIK BHATTACHARJEE <kabonline07@ yahoo.com> wrote:

From: KAUSHIK BHATTACHARJEE <kabonline07@ yahoo.com>
Subject: Re: [Statisticians_ group] Cauchy,Chi square distribution
To: Statisticians_ group@yahoogroup s.co.in
Date: Tuesday, 16 June, 2009, 10:20 AM

Cauchy is t-distribution with 1 df---. t-distribution  is  suitable for modelling rvs which are supposed to have  fat tailed(compared to normal) distributions (e.g. Financial returns in higher frequency like daily or intra-day).
I have modelling experience in regression where the errror terms taht have sufficent reasopn to believe non-normal ----I have tried to model them using t-distrbution. .....
 
Kaushik Bhattacharjee
 


From: vikas ait <vikasait@yahoo. co.in>
To: Statisticians_ group@yahoogroup s.co.in
Sent: Monday, June 15, 2009 6:41:37 PM
Subject: [Statisticians_ group] Cauchy,Chi square distribution


Dear All,
 
I work in software industry and most of data I synthesisie is continuous in nature.
I generally use histogram to understand vraiations using basis of normal disribution .(mean=median= mode)
I am curious to learn what and how part of  chi square and cauchy distibution.
Has anyone used the above distributions? , if yes can you throw more light on it.
Seeking guidance on it.
 
 
Regards,
Vikas


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Bollywood news, movie reviews, film trailers and more! Click here.


#3562 From: vikas ait <vikasait@...>
Date:: Tue Jun 16, 2009 6:53 am
Subject:: Re: Cauchy,Chi square distribution
vikasait
Offline Offline
Send Email Send Email
 
Kaushik ,
Thanks for the input.
This makes me a little familiar with Cauchy distribution.
Will appreciate, if you can give me some more clarity on
what and how part of chi square.
and how does chi square, Cauchy, normal distributions differ conceptually.
Regards,
Vikas


--- On Tue, 16/6/09, KAUSHIK BHATTACHARJEE <kabonline07@...> wrote:

From: KAUSHIK BHATTACHARJEE <kabonline07@...>
Subject: Re: [Statisticians_group] Cauchy,Chi square distribution
To: Statisticians_group@...
Date: Tuesday, 16 June, 2009, 10:20 AM

Cauchy is t-distribution with 1 df---. t-distribution  is  suitable for modelling rvs which are supposed to have  fat tailed(compared to normal) distributions (e.g. Financial returns in higher frequency like daily or intra-day).
I have modelling experience in regression where the errror terms taht have sufficent reasopn to believe non-normal ----I have tried to model them using t-distrbution. .....
 
Kaushik Bhattacharjee
 


From: vikas ait <vikasait@yahoo. co.in>
To: Statisticians_ group@yahoogroup s.co.in
Sent: Monday, June 15, 2009 6:41:37 PM
Subject: [Statisticians_ group] Cauchy,Chi square distribution


Dear All,
 
I work in software industry and most of data I synthesisie is continuous in nature.
I generally use histogram to understand vraiations using basis of normal disribution .(mean=median= mode)
I am curious to learn what and how part of  chi square and cauchy distibution.
Has anyone used the above distributions? , if yes can you throw more light on it.
Seeking guidance on it.
 
 
Regards,
Vikas


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Bollywood news, movie reviews, film trailers and more! Click here.

#3561 From: "Ahmad Khedri" <ahmad_khedri509@...>
Date:: Tue Jun 16, 2009 6:37 am
Subject:: iran pictures
ahmad_khedri509
Offline Offline
Send Email Send Email
 
these are some iran pictures that are "clear evidence"

if these aren't enough please take a tour over BBC, CNN,...

all of these "clear evidence" isn't 5% of press on people

sorry, sorry, sorry

#3560 From: "Ahmad Khedri" <ahmad_khedri509@...>
Date:: Tue Jun 16, 2009 6:25 am
Subject:: iran pictures
ahmad_khedri509
Offline Offline
Send Email Send Email
 
these pix are "clear evidence".

if these aren't enogh, take a tour over BBC, CNN, ...

all of these "clear evidence" shows 5% of actually news.

please help man.

#3559 From: Aziz Farooq <azizfar@...>
Date:: Tue Jun 16, 2009 5:53 am
Subject:: Re: IRAN
azizfar
Offline Offline
Send Email Send Email
 
Sorry Mr. Ahmed.
 
We cannot spread such news without evidence.
It is very easy to spread rumours. One must be very careful while judging the quality of the message. If there is not clear evidence what is the purpose of spreading such a news.
 
Thanks and hope you understand the situation.
 
Aziz

 


From: Ahmad Khedri <ahmad_khedri509@...>
To: Statisticians_group@...
Sent: Tuesday, June 16, 2009 8:21:29 AM
Subject: [Statisticians_group] IRAN

hello all friends

i have master degree in statistics and i live in iran-tehran.

4 day ago we have a president election in iran. last president (ahmadi nejad) ,as a new candidate says many lies with statistics.

and after election the secret army kills and disturb many peoples in citys.

i and all of peaples are vert depress an future is unknown.

please help iran peaples with emailing this text to all of your friends.
please help.

best regards



#3558 From: "Ahmad Khedri" <ahmad_khedri509@...>
Date:: Tue Jun 16, 2009 5:21 am
Subject:: IRAN
ahmad_khedri509
Offline Offline
Send Email Send Email
 
hello all friends

i have master degree in statistics and i live in iran-tehran.

4 day ago we have a president election in iran. last president (ahmadi nejad)
,as a new candidate says many lies with statistics.

and after election the secret army kills and disturb many peoples in citys.

i and all of peaples are vert depress an future is unknown.

please help iran peaples with emailing this text to all of your friends.
please help.

best regards

#3557 From: KAUSHIK BHATTACHARJEE <kabonline07@...>
Date:: Tue Jun 16, 2009 4:50 am
Subject:: Re: Cauchy,Chi square distribution
kabonline07
Offline Offline
Send Email Send Email
 
Cauchy is t-distribution with 1 df---. t-distribution  is  suitable for modelling rvs which are supposed to have  fat tailed(compared to normal) distributions (e.g. Financial returns in higher frequency like daily or intra-day).
I have modelling experience in regression where the errror terms taht have sufficent reasopn to believe non-normal ----I have tried to model them using t-distrbution......
 
Kaushik Bhattacharjee
 


From: vikas ait <vikasait@...>
To: Statisticians_group@...
Sent: Monday, June 15, 2009 6:41:37 PM
Subject: [Statisticians_group] Cauchy,Chi square distribution


Dear All,
 
I work in software industry and most of data I synthesisie is continuous in nature.
I generally use histogram to understand vraiations using basis of normal disribution .(mean=median= mode)
I am curious to learn what and how part of  chi square and cauchy distibution.
Has anyone used the above distributions? , if yes can you throw more light on it.
Seeking guidance on it.
 
 
Regards,
Vikas


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