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Re: [hydrologymodel] conversion

(Members are requested to post the messages in English only - Moderator)

Espero que le sea de Utilidad el adjunto lo deduje
Estela Polegritti

1 watt= 1 kg.m2seg-3

1watt / m2 = ( 1 kg m2 seg –3 ) m-2

1 watt / m2 = 1 kg seg-3

Para que se produzca la evaporación por unidad de área y por unidad de
fuerza durante un mes, se necesita un Newton por el área total en metros
cuadrados por los segundos del mes, 2592000.

1 N = 1 Kg. m s-2

área(m2) 2592000 seg/ mes


Dear all,
>
> I have estimated monthly PET using Mintz-Thornthwaite method. The output
> is in W/sq.m (watts per sq.m). I want it to convert from W/sq.m to
> mm/month or m/month. I went through a lot of literature but I am unable to
> find the conversion factor for it. Can u tell me the conversion factor or
> how to convert it.






Thu Mar 2, 2006 1:26 pm

e.polegritti@...
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Message #391 of 727 |
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Dear all, I have estimated monthly PET using Mintz-Thornthwaite method. The output is in W/sq.m (watts per sq.m). I want it to convert from W/sq.m to...
Shruthi BV
shruthi_ces
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Mar 2, 2006
10:25 am

With the following I guess you can find what you need: Radiation : 1 cal cm-2 d-1 --> 0.041868 MJ m-2 d-1 1 MJ m-2 d-1 --> 23.884 cal cm-2 d-1 --> 0.408 mm...
Gutierrez Alexis
gutierrez_al...
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Mar 2, 2006
12:23 pm

Shruthi, Find from any physical hydrology text book, what is the energy required for evapoarting 0.001 cum of water. (So, that much energy in watts is required...
S V Vijayakumar
vkumarsv@...
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Mar 2, 2006
12:28 pm

(Members are requested to post the messages in English only - Moderator) Espero que le sea de Utilidad el adjunto lo deduje Estela Polegritti 1 watt= 1...
e.polegritti@...
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Mar 3, 2006
3:58 am
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